Armstrong Number Program
In case of an Armstrong number of 3 digits, the sum of cubes of each digits is equal to the number itself. For example: 153 = 1*1*1 + 5*5*5 + 3*3*3 // 153 is an Armstrong number. Armstrong number in Java. Here we written the code in four different ways standard, using for loop, recursion, while loop and also with different examples as like.
A positive integer is called an Armstrong number of order n if abcd. = an + bn + cn + dn +. In case of an Armstrong number of 3 digits, the sum of cubes of each digits is equal to the number itself.
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For example: 153 = 1.1.1 + 5.5.5 + 3.3.3 // 153 is an Armstrong number. Source Code: Check Armstrong number (for 3 digits) # Python program to check if the number provided by the user is an Armstrong number or not # take input from the user # num = int(input('Enter a number: ')) # initialize sum sum = 0 # find the sum of the cube of each digit temp = num while temp 0: digit = temp% 10 sum += digit. 3 temp //= 10 # display the result if num sum: print(num,'is an Armstrong number') else: print(num,'is not an Armstrong number'). Output 1 Enter a number: 663 663 is not an Armstrong number Output 2 Enter a number: 407 407 is an Armstrong number Here, we ask the user for a number and check if it is an Armstrong number. We need to calculate the sum of cube of each digit. So, we initialize the sum to 0 and obtain each digit number by using the. Remainder of a number when it is divide by 10 is the last digit of that number.
Armstrong Number Programming In Vb
We take the cubes using exponent operator. Finally, we compare the sum with the original number and conclude that it is Armstrong number if they are equal. Source Code: Check Armstrong number of n digits.